Option 2 : Increased by \(108\frac{1}{3}\)%

**Formula used:**

Volume of cylinder = πr^{2}h

**Calculations:**

v = πr^{2}h

\(\left( {16\frac{2}{3}} \right)\% = \frac{1}{6}\)

A/Q π × 6^{2} × 1 : π × 5^{2} × 3

⇒ v_{1} : v_{2} = 12 : 25

% increase = 13/12 = 1 + 1/12 = 100% + \(8\frac{1}{3}\)%

**∴**** % increase is \(108\frac{1}{3}\)%**